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This was causing me a bit of grief...
I created a dictionary from a list
l = ['a','b','c'] d = dict.fromkeys(l, [0,0]) # initializing dictionary with [0,0] as values d['a'] is d['b'] # returns True How can I make each value of the dictionary a seperate list? Is this possible without iterating over all keys and setting them equal to a list? I'd like to modify one list without changing all the others.
769
No, there is no guaranteed order for the list of keys returned by the keys() function. In most cases, the key list is returned in the same order as the insertion, however, that behavior is NOT guaranteed and should not be depended on by your program.
The methods dict. keys() and dict. values() return lists of the keys or values explicitly. There's also an items() which returns a list of (key, value) tuples, which is the most efficient way to examine all the key value data in the dictionary.
In Python to get all values from a dictionary, we can use the values() method. The values() method is a built-in function in Python and returns a view object that represents a list of dictionaries that contains all the values.
Example 1: Python Dictionary fromkeys() with Key and Value In the above example, we have used the fromkeys() method to create the dictionary with the given set of keys and string value . Here, the fromkeys() method creates a new dictionary named vowels from keys and value .
You could use a dict comprehension:
>>> keys = ['a','b','c'] >>> value = [0, 0] >>> {key: list(value) for key in keys} {'a': [0, 0], 'b': [0, 0], 'c': [0, 0]} If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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