finding first day of the month in python

Question

I'm trying to find the first day of the month in python with one condition: if my current date passed the 25th of the month, then the first date variable will hold the first date of the next month instead of the current month. I'm doing the following:

import datetime 
todayDate = datetime.date.today()
if (todayDate - todayDate.replace(day=1)).days > 25:
    x= todayDate + datetime.timedelta(30)
    x.replace(day=1)
    print x
else:
    print todayDate.replace(day=1)

is there a cleaner way for doing this?

Answer 1

Can be done on the same line using date.replace:

from datetime import datetime  datetime.today().replace(day=1) 

Answer 2

This is a pithy solution.

import datetime   todayDate = datetime.date.today() if todayDate.day > 25:     todayDate += datetime.timedelta(7) print todayDate.replace(day=1) 

One thing to note with the original code example is that using timedelta(30) will cause trouble if you are testing the last day of January. That is why I am using a 7-day delta.

Answer 3

Use dateutil.

from datetime import date
from dateutil.relativedelta import relativedelta

today = date.today()
first_day = today.replace(day=1)
if today.day > 25:
    print(first_day + relativedelta(months=1))
else:
    print(first_day)

Answer 4

from datetime import datetime

date_today = datetime.now()
month_first_day = date_today.replace(day=1, hour=0, minute=0, second=0, microsecond=0)
print(month_first_day)