Given a standard view model implementation, when a property changes, is there any way to determine the originator of the change? In other words, in the following view model, I would like the "sender" argument of the "PropertyChanged" event to be the actual object that called the Prop1
setter:
public class ViewModel : INotifyPropertyChanged
{
public double Prop1
{
get { return _prop1; }
set
{
if (_prop1 == value)
return;
_prop1 = value;
// here, can I determine the sender?
RaisePropertyChanged(propertyName: "Prop1", sender: this);
}
}
private double _prop1;
// TODO implement INotifyPropertyChanged
}
Alternatively, is it possible to apply CallerMemberNameAttribute
to a property setter?
If I understood correctly, you're asking about the caller of the setter. That means, the previous method call in the call stack before getting to the setter itself (which is a method too).
Use StackTrace.GetFrames
method for this. For example (taken from http://www.csharp-examples.net/reflection-callstack/):
using System.Diagnostics;
[STAThread]
public static void Main()
{
StackTrace stackTrace = new StackTrace(); // get call stack
StackFrame[] stackFrames = stackTrace.GetFrames(); // get method calls (frames)
// write call stack method names
foreach (StackFrame stackFrame in stackFrames)
{
Console.WriteLine(stackFrame.GetMethod().Name); // write method name
}
}
The output:
Main
nExecuteAssembly
ExecuteAssembly
RunUsersAssembly
ThreadStart_Context
Run
ThreadStart
Basically, what you're asking for would be stackFrames[1].GetMethod().Name
.
My first approach to your problem would be to derive from PropertyEventArgs
. The new class would have a member called, for instance PropertyChangeOrigin
in addition to PropertyName
. When you invoke the RaisePropertyChanged
, you supply an instance of the new class with the PropertyChangeOrigin
set from the information gleaned from the CallerMemberName
attribute. Now, when you subscribe to the event, the subscriber could try casting the eventargs
to your new class and use the information if the cast is successful.
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