How can I separate out each bit from a byte?

Question

I'm very new to C# (and C in general for that matter) I'm getting a byte value returned from an external source that represents the states of 8 input pins on the port of an IO device so I get a value of 0-255 representing the binary pattern present on the port.

How can I strip out the individual bits and set them as bool vars, so doing something like this:

if (inputBuffer[1] == 1)
{
     IO.Input0 = true;
     IO.Input1 = false;
     IO.Input2 = false;
     IO.Input3 = false;
     IO.Input4 = false;
     IO.Input5 = false;
     IO.Input6 = false;
     IO.Input7 = false;
}    

I'm probably overexplaining what I'm trying to achieve but thought this gives the best example although highly impractical, how can I better achieve this to set the variables based on a byte value of 0-255.

Answer 1

Use a bitwise-and (&). Assuming Input0 represents the least significant bit:

IO.Input0 = (inputBuffer & 0x01) == 0x01;
IO.Input1 = (inputBuffer & 0x02) == 0x02;
IO.Input2 = (inputBuffer & 0x04) == 0x04;
IO.Input3 = (inputBuffer & 0x08) == 0x08;
IO.Input4 = (inputBuffer & 0x10) == 0x10;
IO.Input5 = (inputBuffer & 0x20) == 0x20;
IO.Input6 = (inputBuffer & 0x40) == 0x40;
IO.Input7 = (inputBuffer & 0x80) == 0x80;

---

You can also implement an extension method like the following:

public static bool IsBitSet(this byte b, int bit)
{
    if(bit < 0 || bit > 7)
        throw new ArgumentOutOfRangeException("bit must be between 0 and 7");

    byte bitToCheck = (byte)(0x01 << bit);

    return (b & bitToCheck) == bitToCheck;
}

Which you could then call like:

IO.Input4 = inputBuffer.IsBitSet(4);

Answer 2

Use a bitmask and the &-operator to figure this out

byte b = 100;

if(b&1 == 1) { } //bit 1 is set
if(b&2 == 2) { } //bit 2 is set
if(b&4 == 4) { } //bit 3 is set
...