I feel stupid asking such a simple question, but is there an easy way to determine whether an Integer is even or odd?
Definition 1: “Even numbers are those numbers which are divisible by 2 and odd numbers which are not divisible by two”. Definition 2: “Even numbers are those which when divided by 2 leaves no remainder or as 0 and Odd numbers are those numbers which when divided by 2 leaves a remainder of 1”.
If the units digit (or ones digit) is 1,3, 5, 7, or 9, then the number is called an odd number, and if the units digit is 0, 2, 4, 6, or 8, then the number is called an even number. Thus, the set of integers can be partitioned into two sets based on parity: the set of even (or parity 0) integers.
An odd number is a number that is not divisible by 2. The remainder in the case of an odd number is always “1”. 11 is an odd number.
A number is even if, when divided by two, the remainder is 0. A number is odd if, when divided by 2, the remainder is 1.
if ((n % 2) == 0) {
// number is even
}
else {
// number is odd
}
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