Detect number of processes running with the same name

Question

Any ideas of how to write a function that returns the number of instances of a process is running?

Perhaps something like this?

function numInstances([string]$process)
{
    $i = 0
    while(<we can get a new process with name $process>)
    {
        $i++
    }

    return $i
}

Edit: Started to write a function... It works for a single instance but it goes into an infinite loop if more than one instance is running:

function numInstances([string]$process)
{
$i = 0
$ids = @()
while(((get-process $process) | where {$ids -notcontains $_.ID}) -ne $null)
    {
    $ids += (get-process $process).ID
    $i++
    }

return $i
}

Answer 1

function numInstances([string]$process)
{
    @(get-process -ea silentlycontinue $process).count
}

EDIT: added the silently continue and array cast to work with zero and one processes.

Answer 2

There is a nice one-liner : (ps).count

Answer 3

(Get-Process | Where-Object {$_.Name -eq 'Chrome'}).count

This will return you the number of processes with same name running. you can add filters to further format your data.

Answer 4

Its much easier to use the built-in cmdlet group-object:

 get-process | Group-Object -Property ProcessName