I'm currently wring a Cocoa application which needs to execute some (console) applications which are optimized for 32 and 64 bit. Because of this I would like to detect what CPU architecture the application is running on so I can start the correct console application.
So in short: how do I detect if the application is running on a 64 bit OS?
Edit: I know about the Mach-O fat binaries, that was not my question. I need to know this so I can start another non bundled (console) application. One that is optimized for x86 and one for x64.
There is a super-easy way. Compile two versions of the executable, one for 32-bit and one for 64-bit and combine them with lipo. That way, the right version will always get executed.
gcc -lobjc somefile.m -o somefile -m32 -march=i686
gcc -lobjc somefile.m -o somefile2 -m64 -march=x86_64
lipo -create -arch i686 somefile -arch x86_64 somefile2 -output somefileUniversal
Edit: or just compile a universal binary in the first place with gcc -arch i686 -arch x86_64
In response to OP's comment:
if(sizeof(int*) == 4)
//system is 32-bit
else if(sizeof(int*) == 8)
//system is 64-bit
EDIT: D'oh! I didn't realise you'd need runtime checking... Going through the output of sysctl -A
, two variables look potentially useful. Try parsing the output of sysctl hw.optional.x86_64
and sysctl hw.cpu64bit_capable
. I don't have a 32-bit Mac around to test this, but both these are set to 1 in Snow Leopard on a Core2Duo Mac.
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