Dereferencing a temporary unique_ptr

Question

unique_ptr<A> myFun()
{
    unique_ptr<A> pa(new A());
    return pa;
}

const A& rA = *myFun();

This code compiles but rA contains garbage. Can someone explain to me why is this code invalid?

Note: if I assign the return of myFun to a named unique_ptr variable before dereferencing it, it works fine.

Answer 1

The unique_ptr will pass the ownership to another unique_ptr, but in your code there is nothing to capture the ownership from the returning pointer. In other words, It can not transfer the ownership, so it will be destructed. The proper way is:

unique_ptr<A> rA = myFun(); // Pass the ownership

or

const A rA = *myFun(); // Store the values before destruction

In your code, the returning pointer will be desructed and the reference is refering to an object which is destructing soon, after that using this reference invokes an undefined behavior.