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Putting all the maintainability and reading issues aside, can these lines of code generate undefined behavior?
float a = 0, b = 0;
float& x = some_condition()? a : b;
x = 5;
cout << a << ", " << b;
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There are three steps to initializing a reference variable from scratch: declaring the reference variable; using the new operator to build an object and create a reference to the object; and. storing the reference in the variable.
An rvalue reference can be initialized with an lvalue in the following contexts: A function lvalue. A temporary converted from an lvalue. An rvalue result of a conversion function for an lvalue object that is of a class type.
To initialize the const value using constructor, we have to use the initialize list. This initializer list is used to initialize the data member of a class. The list of members, that will be initialized, will be present after the constructor after colon. members will be separated using comma.
No, it's just fine. It would not create undefined behavior in this code. You will just change value of a or b to 5, according to condition.
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