How do I delete a pointer and the object it's pointing to?
Will the code below delete the object?
Object *apple;
apple = new Object();
delete apple;
And what happens if the pointer is not deleted, and gets out of scope?
Object *apple;
apple = new Object();
This might be a very basic question, but I'm coming from Java.
Pointer to object is not destroyed, value or memory block pointed by pointer is destroyed.
When delete is used to deallocate memory for a C++ class object, the object's destructor is called before the object's memory is deallocated (if the object has a destructor). If the operand to the delete operator is a modifiable l-value, its value is undefined after the object is deleted.
The address of the pointer does not change after you perform delete on it. The space allocated to the pointer variable itself remains in place until your program releases it (which it might never do, e.g. when the pointer is in the static storage area).
Yes, it's totally fine to reuse a pointer to store a new memory address after deleting the previous memory it pointed to.
Your first code snippet does indeed delete the object. The pointer itself is a local variable allocated on the stack. It will be deallocated as soon as it goes out of scope.
That brings up the second point--if the pointer goes out of scope before you deallocate the object you allocated on the heap, you will never be able to deallocate it, and will have a memory leak.
Hope this helps.
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