My understanding is that C++ allows static const members to be defined inside a class so long as it's an integer type.
Why, then, does the following code give me a linker error?
#include <algorithm> #include <iostream> class test { public: static const int N = 10; }; int main() { std::cout << test::N << "\n"; std::min(9, test::N); }
The error I get is:
test.cpp:(.text+0x130): undefined reference to `test::N' collect2: ld returned 1 exit status
Interestingly, if I comment out the call to std::min, the code compiles and links just fine (even though test::N is also referenced on the previous line).
Any idea as to what's going on?
My compiler is gcc 4.4 on Linux.
“static const” is basically a combination of static(a storage specifier) and const(a type qualifier). The static determines the lifetime and visibility/accessibility of the variable.
A static data member can be of any type except for void or void qualified with const or volatile. You cannot declare a static data member as mutable.
For std::string , it must be defined outside the class definition and initialized there. static members must be defined in one translation unit to fulfil the one definition rule. If C++ allows the definition below; struct C { static const string b = "hi"; };
We can define class members static using static keyword. When we declare a member of a class as static it means no matter how many objects of the class are created, there is only one copy of the static member. A static member is shared by all objects of the class.
My understanding is that C++ allows static const members to be defined inside a class so long as it's an integer type.
You are sort of correct. You are allowed to initialize static const integrals in the class declaration but that is not a definition.
Interestingly, if I comment out the call to std::min, the code compiles and links just fine (even though test::N is also referenced on the previous line).
Any idea as to what's going on?
std::min takes its parameters by const reference. If it took them by value you'd not have this problem but since you need a reference you also need a definition.
Here's chapter/verse:
9.4.2/4 - If a
static
data member is ofconst
integral orconst
enumeration type, its declaration in the class definition can specify a constant-initializer which shall be an integral constant expression (5.19). In that case, the member can appear in integral constant expressions. The member shall still be defined in a namespace scope if it is used in the program and the namespace scope definition shall not contain an initializer.
See Chu's answer for a possible workaround.
Bjarne Stroustrup's example in his C++ FAQ suggests you are correct, and only need a definition if you take the address.
class AE { // ... public: static const int c6 = 7; static const int c7 = 31; }; const int AE::c7; // definition int f() { const int* p1 = &AE::c6; // error: c6 not an lvalue const int* p2 = &AE::c7; // ok // ... }
He says "You can take the address of a static member if (and only if) it has an out-of-class definition". Which suggests it would work otherwise. Maybe your min function invokes addresses somehow behind the scenes.
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