When, for example, making a colorscheme, how can one define #40ffff as "UglyColor" (i.e. as a variable) ?
Possible / not possible ?
It's not possible with the built in syntax. However, it can be done if the you make your own syntax:
let UglyColor = '#40ffff'
let Greenish = '#00dd00'
let MyStyle = 'bold'
exe 'hi Keyword gui=' . MyStyle . ' guifg=' . UglyColor
exe 'hi Comment guifg=' . Greenish
You could then take this further by creating a dictionary:
let UglyColor = '#40ffff'
let Greenish = '#00dd00'
let ColourAssignment = {}
let ColourAssignment['Keyword'] = {"GUIFG": UglyColor, "GUI": "Bold"}
let ColourAssignment['Comment'] = {"GUIFG": Greenish}
And then process it with something like this:
for key in keys(ColourAssignment)
let s:colours = ColourAssignment[key]
if has_key(s:colours, 'GUI')
let gui = s:colours['GUI']
else
let gui='NONE'
endif
if has_key(s:colours, 'GUIFG')
let guifg = s:colours['GUIFG']
else
let guifg='NONE'
endif
if has_key(s:colours, 'GUIBG')
let guibg = s:colours['GUIBG']
else
let guibg='NONE'
endif
if key =~ '^\k*$'
execute "hi ".key." term=".term." cterm=".cterm." gui=".gui." ctermfg=".ctermfg." guifg=".guifg." ctermbg=".ctermbg." guibg=".guibg." guisp=".guisp
endif
This is how my Bandit colour scheme works (with a bit more logic in there for auto-generating cterm colours, light background colours and a syntax file so that the colour scheme self-highlights). Feel free to have a look at that one and steal the functions and format for your own colour scheme.
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