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Declaring a hex constant in VB.NET

How can I convert the following C# hexadecimal into a VB.NET hexadecimal?

private const UInt32 temp = 0xE6359A60;

I tried the following, but it doesn't work.

Public Const temp As System.UInt32 = 0xE6359A60
like image 519
Ali Avatar asked Apr 20 '12 05:04

Ali


2 Answers

C# uses 0x and VB.NET uses &H as the prefix to specify hexadecimal numbers. try this.

Public Const temp As Integer = &HE6359A60

Sub Main

End Sub

And it could be as Uint also:

Public Const temp As UInt32 = &HE6359A60UI

Sub Main

End Sub

Check MSDN's Type Characters (Visual Basic) documentation for defining hexadecimal and octal literals:

The compiler normally construes an integer literal to be in the decimal (base 10) number system. You can force an integer literal to be hexadecimal (base 16) with the &H prefix, and you can force it to be octal (base 8) with the &O prefix. The digits that follow the prefix must be appropriate for the number system.

References:

  • Hex number (not ASCII hex value) to string in VB.NET (Stack Overflow)
  • What does &H57 represent and how can I translate it for C#? (Stack Overflow)
like image 115
Niranjan Singh Avatar answered Nov 15 '22 21:11

Niranjan Singh


Public Const temp As Integer = &H6359A60

Prefix it with &H

like image 23
Alex Avatar answered Nov 15 '22 20:11

Alex