I have a problem with my a bash script. What I do is assign variables like this.
for ((i=START;i<=END;i++)
declare var$i=$(something)
done
And it works, but now I have a problem with finnish characters like å, ä, ö. What declare says is something like this
bash:declare 'wörd' not a valid identifier
Though it works fine if I do it like this
declare var2=$(sömething)
I can convert the characters with sed but it's better to have them like always, so this is a last resort solution. So I would like to know how can I assign variables like
var$i
with the finnish characters. The wörd word is part of the output of my command 'something'. When there are two words or more only the word(s) that contain the character ö , ä and so on are not assigned to the variable, so if the output of the command was "something wörd" then the only thing that is being shown with echo is something.
bash
simply does not allow identifiers using characters other than A-Z, a-z, 0-9, and _. However, the error you describe is just a side effect of that limitation. declare
is a command which takes a string argument that looks like an assignment statement, but the semantics are slightly different. Consider this command:
foo () {
echo "something wörd"
}
In an assignment statement, the right-hand side does not undergo word splitting, so you don't have to quote the command substitution. The following works fine:
$ word3=$(foo)
$ echo "$word"
something wörd
With declare
, however, the command substitution does undergo word splitting, so when you write
$ i=3
$ declare word$i=$(foo)
it's equivalent to the command
$ declare word3=something wörd
which passes two names for declare
to create, word3
(which gets a value) and wörd
(which is an invalid name). declare word3="something wörd"
would work fine; the shell's word-splitting is already done by the time declare
gets the argument.
With declare
, then, you need to quote the command substitution (or the entire string) in order for the entire output to be treated as the value for the new variable.
$ i=3
$ declare "word$i=$(foo)"
$ echo "$word3"
something wörd
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