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>>> a = "2016-03-22 12:33:45.7565"
>>> datetime.datetime.strptime(a, "%Y-%m-%d %H:%M:%f")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/local/Cellar/python/2.7.11/Frameworks/Python.framework/Versions/2.7/lib/python2.7/_strptime.py", line 328, in _strptime
data_string[found.end():])
ValueError: unconverted data remains: .7565
>>> datetime.datetime.strptime(a, "%Y-%m-%d %H:%M:%S")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/local/Cellar/python/2.7.11/Frameworks/Python.framework/Versions/2.7/lib/python2.7/_strptime.py", line 328, in _strptime
data_string[found.end():])
ValueError: unconverted data remains: .7565
I have used %S and %f but how I can handle seconds if that is type float?
Any help would be appreciated
361
Use the total_seconds() method of a timedelta object to get the number of seconds since the epoch. Use the timestamp() method. If your Python version is greater than 3.3 then another way is to use the timestamp() method of a datetime class to convert datetime to seconds.
Use the timedelta() constructor and pass the seconds value to it using the seconds argument. The timedelta constructor creates the timedelta object, representing time in days, hours, minutes, and seconds ( days, hh:mm:ss.ms ) format. For example, datetime.
Use the time. time() function to get the current time in seconds since the epoch as a floating-point number. This method returns the current timestamp in a floating-point number that represents the number of seconds since Jan 1, 1970, 00:00:00. It returns the current time in seconds.
The digits after the decimal point are microseconds, and are formatted separately from the seconds:
>>> a = "2016-03-22 12:33:45.7565"
>>> datetime.datetime.strptime(a, "%Y-%m-%d %H:%M:%S.%f")
datetime.datetime(2016, 3, 22, 12, 33, 45, 756500)
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