Date/Time Difference in Oracle for same field in different rows

Question

I have the below view, what I need to do is to get the date difference of the field ActionDate between each 2 records having the same Vehicle AND OrderCode, how can I achieve this in Oracle database.

Also taking into consideration that the dates subtracted should be the one having the Mode O - Mode I

I need to get the list of the differences in order to get the average of that time.

Thanks for helping.

Answer 1

You could use the analytic LAG() OVER() function to get the difference between the dates.

For example,

SQL> WITH t AS
  2  (
  3    select 'O' as "MODE", 'V1234567890' as  Vehicle, '1411196232' as OrderCode, to_date('2014-11-19 16:34:35','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
  4    union all
  5    select 'I' as "MODE", 'V1234567890' as  Vehicle, '1411196232' as OrderCode, to_date('2014-11-19 15:27:09','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
  6    union all
  7    select 'O' as "MODE", 'V2987654321' as  Vehicle, '1411206614' as OrderCode, to_date('2014-11-20 14:03:02','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
  8    union all
  9    select 'I' as "MODE", 'V2987654321' as  Vehicle, '1411206614' as OrderCode, to_date('2014-11-20 13:47:02','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
 10    union all
 11    select 'O' as "MODE", 'V2987654321' as  Vehicle, '1411185798' as OrderCode, to_date('2014-11-20 01:40:58','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
 12    union all
 13    SELECT 'I' AS "MODE", 'V2987654321' AS  Vehicle, '1411185798' AS OrderCode, to_date('2014-11-20 00:47:02','yyyy-mm-dd hh24:mi:ss') AS ActionDate FROM dual
 14  )
 15  SELECT "MODE",
 16    Vehicle,
 17    OrderCode,
 18    TO_CHAR(ActionDate,'yyyy-mm-dd hh24:mi:ss') dt,
 19    TO_CHAR(LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate),'yyyy-mm-dd hh24:mi:ss') lag_dt,
 20    ActionDate - LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate) diff
 21  FROM t;

M VEHICLE     ORDERCODE  DT                  LAG_DT                    DIFF
- ----------- ---------- ------------------- ------------------- ----------
I V1234567890 1411196232 2014-11-19 15:27:09
O V1234567890 1411196232 2014-11-19 16:34:35 2014-11-19 15:27:09 .046828704
I V2987654321 1411185798 2014-11-20 00:47:02
O V2987654321 1411185798 2014-11-20 01:40:58 2014-11-20 00:47:02 .037453704
I V2987654321 1411206614 2014-11-20 13:47:02
O V2987654321 1411206614 2014-11-20 14:03:02 2014-11-20 13:47:02 .011111111

6 rows selected.

SQL>

NOTE: The WITH clause is to build the sample data, in your case you need to use your actual table_name:

SELECT "MODE",
  Vehicle,
  OrderCode,
  TO_CHAR(ActionDate,'yyyy-mm-dd hh24:mi:ss') dt,
  TO_CHAR(LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate),'yyyy-mm-dd hh24:mi:ss') lag_dt,
  ActionDate - LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate) diff
FROM your_table;

I have put the TO_CHAR just for demonstration purpose, your desired output is the DIFF column. Regarding the MODE, you could add it to the filter predicate.