Case when a value is different to other value, SQL Server

Question

I have this table structure for table prices:

CREATE TABLE prices
(
     id int, 
     priceFrom int, 
     priceUp int
);

INSERT INTO prices (id, priceFrom, priceUp)
VALUES (1, 23, 23), (2, 0, 0), (3, 12, 13),
       (4, 40, 40), (5, 15, 15), (6, 0, 0);

This is the result:

I have this query:

select 
    pricefrom, priceup,
    case
        when pricefrom = 0 then null
        when priceFrom <> priceUp then priceFrom + ' - ' + priceUp
        when priceFrom = priceUp then priceFrom
    end as FinalPrice
from 
    prices

what I need is to do a case when

1. pricefrom = 0 then show null
2. pricefrom = priceup then show the price
3. At least if pricefrom != priceup I want to show for example this: 12(pricefrom) - 13(priceup)

but in my query in this line:

I try to do this with <> but in the result appears the sum for both numbers:

How can I fix this?

Answer 1

I think you're looking for the concat function here.

 select pricefrom, priceup,
case
when pricefrom = 0 then null
when priceFrom <> priceUp then concat(priceFrom, ' - ', priceUp)
when priceFrom = priceUp then cast(priceFrom as varchar(8))
end as FinalPrice
from prices

This link will probably be helpful

MySQL combine two columns into one column

Answer 2

You have to CAST to VARCHAR:

select pricefrom, priceup,
       case
          when pricefrom = 0 then null
          when priceFrom <> priceUp then concat(cast(priceFrom as varchar(8)),
                                                ' - ', 
                                                cast(priceUp as varchar(8)))
          when priceFrom = priceUp then cast(priceFrom as varchar(8))
       end as FinalPrice
from prices