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I'd like to create a javascript function which can take a generic D3 selection, and append duplicates of it to an SVG object.
Here's a minimum working example:
<!DOCTYPE html>
<meta charset="utf-8">
<body>
<script src="http://d3js.org/d3.v3.min.js"></script>
<script>
svg = d3.select("body").append("svg")
.attr("width", 300)
.attr("height", 300);
circle = svg.append("circle")
.attr("cx", 100)
.attr("cy", 100)
.attr("r", 20)
function clone_selection(x, i) {
for (j = 0; j < i; j++) {
// Pseudo code:
// svg.append(an exact copy of x, with all the attributes)
}
}
clone_selection(circle, 5);
</script>
Mike Bostock said that this was impossible here but that was a while back.
Does anyone have any new thoughts about how this might be achieved? Remember, inside the function clone_selection we have no idea what svg element(s) is/are in x.
296
Here's another possibility: do things the long way. This gets round the problem with using <use> elements where you can't set the style or transform attributes separately.
I'm surprised the amazing d3js library doesn't feature something like this natively, but here's my hack:
function clone_d3_selection(selection, i) {
// Assume the selection contains only one object, or just work
// on the first object. 'i' is an index to add to the id of the
// newly cloned DOM element.
var attr = selection.node().attributes;
var length = attr.length;
var node_name = selection.property("nodeName");
var parent = d3.select(selection.node().parentNode);
var cloned = parent.append(node_name)
.attr("id", selection.attr("id") + i);
for (var j = 0; j < length; j++) { // Iterate on attributes and skip on "id"
if (attr[j].nodeName == "id") continue;
cloned.attr(attr[j].name,attr[j].value);
}
return cloned;
}
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