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Is there some way in R to cut by a defined interval without any breaks?
For example, if I want the values in the exact interval [1,10]; by default cut breaks this interval into smaller intervals.
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The cut function in R allows you to cut data into bins and specify 'cut labels', so it is very useful to create a factor from a continuous variable.
The cut command removes the selected data from its original position, while the copy command creates a duplicate; in both cases the selected data is kept in temporary storage (the clipboard). The data from the clipboard is later inserted wherever a paste command is issued.
To cut unto pre-defined intervals, you can specify a vector of breaks using the breaks parameter.
Define some data:
x <- sample(0:20, 100, replace=TRUE) x Now cut x at 0, 10 and 20:
cut(x, breaks=c(0, 10, 20), include.lowest=TRUE) [1] (10,20] [0,10] [0,10] (10,20] (10,20] (10,20] [0,10] (10,20] (10,20] [10] (10,20] [0,10] (10,20] (10,20] (10,20] [0,10] (10,20] [0,10] [0,10] [19] [0,10] (10,20] [0,10] [0,10] [0,10] (10,20] [0,10] (10,20] (10,20] [28] (10,20] (10,20] [0,10] [0,10] [0,10] [0,10] (10,20] [0,10] [0,10] [37] [0,10] [0,10] (10,20] (10,20] (10,20] (10,20] [0,10] (10,20] [0,10] [46] (10,20] [0,10] (10,20] (10,20] [0,10] [0,10] (10,20] (10,20] (10,20] [55] [0,10] [0,10] (10,20] [0,10] [0,10] [0,10] [0,10] (10,20] (10,20] [64] (10,20] [0,10] [0,10] (10,20] (10,20] (10,20] (10,20] (10,20] (10,20] [73] (10,20] [0,10] [0,10] [0,10] (10,20] [0,10] (10,20] [0,10] (10,20] [82] [0,10] [0,10] (10,20] [0,10] [0,10] [0,10] (10,20] (10,20] [0,10] [91] [0,10] [0,10] (10,20] (10,20] [0,10] [0,10] [0,10] [0,10] (10,20] [100] (10,20] Levels: [0,10] (10,20] If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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