I'm trying to write a custom Json serializer in play for a case class but I don't want it to serialize all the fields of the class. I'm pretty new to Scala, so that is surely the problem but this is what I tried so far:
case class Foo(a: String, b: Int, c: Double)
Now the default way of doing this, as far as I saw in the examples is:
implicit val fooWrites: Writes[Foo] = (
(__ \ "a").write[String] and
(__ \ "b").write[Int]
(__ \ "c").write[Double]
) (unlift(Foo.unapply))
But what if I want to omit "c" from the Json output? I've tried this so far but it doesn't compile:
implicit val fooWritesAlt: Writes[Foo] = (
(__ \ "a").write[String] and
(__ \ "b").write[Int]
) (unlift({(f: Foo) => Some((f.a, f.b))}))
Any help is greatly appreciated!
Instead of specifying a combinator which produces an OWrites instance, one can directly construct an OWrites just as well:
val ignore = OWrites[Any](_ => Json.obj())
implicit val fooWrites: Writes[Foo] = (
(__ \ "a").write[String] and
(__ \ "b").write[Int] and
ignore
) (unlift(Foo.unapply))
This will ignore any value of the case class at that position and simply always return an empty JSON object.
If you are using Playframework 2.2 (not sure about earlier versions, but it should work as well) try this:
implicit val writer = new Writes[Foo] {
def writes(foo: Foo): JsValue = {
Json.obj("a" -> foo.a,
"b" -> foo.b)
}
}
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