For a website I'm developing I need to include some diagonal shaped borders to a div
. These are the main examples which I need to recreate.
double diagonal top border, triangle shaped
Now been scouting the web on how to achieve this, and my first thought as well would be by using ::before
. However I can't get it to work without it being positioned absolute which messes up the entire page.
This is my code I have tried to achieve something like this:
.slider-container{
background-color: $blue;
width: 100%;
overflow: hidden;
position: relative;
.col-md-3{
img{
padding: 40px;
width: 100%;
max-width: 400px;
margin: auto;
}
}
&::before {
background: red;
bottom: 100%;
content: '';
display: block;
height: 100%;
position: absolute;
right: 0;
transform-origin: 100% 100%;
transform: rotate(-15deg);
width: 150%;
}
}
<section id="slider">
<div class="container-fluid">
<div class="row slider-container">
<div class="col-md-3">
<p>imgae 1</p>
</div>
<div class="col-md-3">
<p>imgae 2</p>
</div>
<div class="col-md-3">
<p>imgae 3</p>
</div>
<div class="col-md-3">
<p>imgae 4</p>
</div>
</div>
</div>
</section>
Note: it won't work in here but this is the result I get result
With just css and a bit tweaking based on your divs size you could create something like this:
.myclass {
width: 100px;
height: 100px;
background: linear-gradient(45deg, black 0%, black 26%, transparent 26%), linear-gradient(-45deg, black 0%, black 27%, transparent 27%)
}
.myclass2 {
width: 100px;
height: 100px;
background: linear-gradient(-45deg, blue 0%, blue 27%, transparent 27%), linear-gradient(45deg, blue 0%, blue 26%, red 26%)
}
With transparency:
<div class="myclass">My content here</div>
<br/>
Not as easy with transparent:
<div class="myclass2">My content here</div>
Edit: Just tested this in chrome, you might need special linear-gradients for older/other browsers.
The most simple way to achieve this would probably be to use a background image, though the effect may prove to be inconsistent on smaller devices. For this reason, you may want to consider using a hard-stop gradient.
.grad {
background: lightblue; /* For browsers that don't support gradients */
background: -webkit-linear-gradient(170deg, white 0%, white, 15%, lightblue 15%, lightblue 100%);
background: -o-linear-gradient(170deg, white 0%, white, 15%, lightblue 15%, lightblue 100%);
background: -moz-linear-gradient(170deg, white 0%, white, 15%, lightblue 15%, lightblue 100%);
background: linear-gradient(170deg, white 0%, white, 15%, lightblue 15%, lightblue 100%);
width: 100%;
padding: 20px;
}
<div class="grad">
<h1>Hard-stop gradient</h1>
<p>Using this type of gradient, you can create an angled background without using a background image.</p>
</div>
Using this, you can create a gradient from 0% to 15% that is white on both ends, followed by a gradient from 15% to 100% that's fully black. This completely removes the fading effect, giving you your angled background. It's probably the most efficient way as well since it only requires one line of CSS.
Something like this?
div {
background: yellow;
height: 150px;
overflow: hidden;
position: relative;
width: 300px;
}
div::before {
background: red;
bottom: 100%;
content: '';
display: block;
height: 100%;
position: absolute;
right: 0;
transform-origin: 100% 100%;
transform: rotate(-15deg);
width: 150%;
}
<div></div>
You can use clip-path
.
body {
margin: 0;
padding: 0;
color: #ffffff;
}
.wrapper {
min-height: 100vh;
min-width: 100vw;
max-width: 100vw;
width: 100vw;
background-color: red;
}
.bg {
min-height: 100vh;
min-width: 100vw;
background-color: blue;
clip-path: polygon(80% 0, 100% 0, 100% 100%, 50% 100%);
}
<div class="wrapper">
<div class="bg"></div>
</div>
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With