cron job minute before tomorrow

Question

I am about to trigger a call to a PHP file via curl in a schedule basis. I am thinking of having the script to be executed every 23:59:59 or simply a minute before the day turns tomorrow. Any best approach for this? Quite confused still on the cron settings.

I need to ensure that I run at exactly a second before the next day.

Answer 1

Minutes [0-59]  
|   Hours [0-23]  
|   |   Days [1-31]  
|   |   |   Months [1-12]  
|   |   |   |   Days of the Week [Numeric, 0-6]  
|   |   |   |   |  
*   *   *   *   * home/path/to/command/the_command.sh  




 59 23 * * * home/path/to/command/the_command.sh 

Answer 2

To Execute a script every day at 23:59:00, use the following:

59 23 * * * root /path_to_file_from_root

Seconds cannot be defined using Cron, but this should do for you.

To execute the script at 23:59:59, use the PHP sleep() function to delay the execution of the script by 59 seconds. I would advise 58 seconds though, just to make sure the script doesn't delay until after midnight.

This is very basic, you could make it a little more complex and run tests to ensure that the script is always run at 23:59:59 by retrieving the time and delaying appropriately. This should not be necessary though.

<?php

    // Any work that the script can do without altering the database, do here

    // Delay the script by 58 seconds
    sleep(58);

    // Carry on with the rest of the script here, database updates etc

?>

Answer 3

Start crontab editing by

crontab -e

or by

vi /etc/cronatb

It depends on distro.

59 23 * * * root /path/to/your/php/file.php

Note that "root" column mean name of user under which to start job, maybe will not available on your system.

Try to run

man crontab

for more details