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Creating StringVar Variables in a Loop for Tkinter Entry Widgets

I have a small script that generates a random number of entry widgets. Each one needs a StringVar() so I can assign text to the widget. How can I create these as part of the loop since I won't know ahead of time as to how many there will be?

from Tkinter import *
import random
root = Tk()
a = StringVar()
height = random.randrange(0,5)
width = 1

for i in range(height): #Rows
    value + i = StringVar()
    for j in range(width): #Columns
        b = Entry(root, text="", width=100, textvariable=value+i)
        b.grid(row=i, column=j)

mainloop()
like image 669
user2242044 Avatar asked May 06 '26 01:05

user2242044


2 Answers

The direct answer to your question is to use a list or dictionary to store each instance of StringVar.

For example:

vars = []
for i in range(height):
    var = StringVar()
    vars.append(var)
    b = Entry(..., textvariable=var)

However, you don't need to use StringVar with entry widgets. StringVar is good if you want two widgets to share the same variable, or if you're doing traces on the variable, but otherwise they add overhead with no real benefit.

entries = []
for i in range(height):
    entry = Entry(root, width=100)
    entries.append(entry)

You can insert or delete data with the methods insert and delete, and get the value with get:

for i in range(height):
    value = entries[i].get()
    print "value of entry %s is %s" % (i, value)
like image 85
Bryan Oakley Avatar answered May 08 '26 14:05

Bryan Oakley


Just store them in a list.

vars = []
for i in range(height): #Rows
    for j in range(width): #Columns
        vars.append(StringVar())
        b = Entry(root, text="", width=100, textvariable=vars[-1])
        b.grid(row=i, column=j)

That said, you should probably be storing the Entry widgets themselves in a list, or a 2D list as shown:

entries = []
for i in range(height): #Rows
    entries.append([])
    for j in range(width): #Columns
        entries[i].append(Entry(root, text="", width=100))
        entries[i][j].grid(row=i, column=j)

You can then assign text to each widget with the insert() method:

entries[0][3].insert(0, 'hello')
like image 24
TigerhawkT3 Avatar answered May 08 '26 13:05

TigerhawkT3



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