Creating a Serial Port in code in VB.net

Question

I am trying to create a serial port in VB.net using code only. Because I am creating a class library I cannot use the built-in component. I have tried instantiating a new SeialPort() object, but that does not seem to be enough. I'm sure there is something simple I am missing and any help would be greatly appreciated! Thanks!

P.S. I should add that the problem I am having at this time is getting the code to handle the datareceived event. Other than that it might be working, but I can't tell because of that problem.

Answer 1

If you want to use the events make sure you declare your serialPort object using the 'withevents'. The below example will allow you to connect to a serial port, and will raise an event with the received string.

Imports System.Threading

Imports System.IO

Imports System.Text

Imports System.IO.Ports


Public Class clsBarcodeScanner

Public Event ScanDataRecieved(ByVal data As String)
WithEvents comPort As SerialPort

Public Sub Connect()
    Try
        comPort = My.Computer.Ports.OpenSerialPort("COM5", 9600)
    Catch
    End Try
End Sub

Public Sub Disconnect()

    If comPort IsNot Nothing AndAlso comPort.IsOpen Then
        comPort.Close()
    End If

End Sub

Private Sub comPort_DataReceived(ByVal sender As Object, ByVal e As System.IO.Ports.SerialDataReceivedEventArgs) Handles comPort.DataReceived
    Dim str As String = ""
    If e.EventType = SerialData.Chars Then
        Do
            Dim bytecount As Integer = comPort.BytesToRead

            If bytecount = 0 Then
                Exit Do
            End If
            Dim byteBuffer(bytecount) As Byte


            comPort.Read(byteBuffer, 0, bytecount)
            str = str & System.Text.Encoding.ASCII.GetString(byteBuffer, 0, 1)

        Loop
    End If

    RaiseEvent ScanDataRecieved(str)

End Sub
End Class

Answer 2

I found this article to be quite good.

The code i wrote from it is:

port = new System.IO.Ports.SerialPort(name, 4800, System.IO.Ports.Parity.None, 8, System.IO.Ports.StopBits.One);
port.DataReceived += new System.IO.Ports.SerialDataReceivedEventHandler(port_DataReceived);
port.Open();

void port_DataReceived(object sender, System.IO.Ports.SerialDataReceivedEventArgs e)
{
    buffer = port.ReadLine();
    // process line
}

Sorry it's C# but...

The only issue I have with it is if the port is dropped while it's open, the app seems to fail on exit.