Create page break using OpenXml

Question

I use OpenXml to create Word document with simple text and some tables under this text. How can I force Paragraph with this text to show always on new page? Maybe this paragraph should be some Header but I'm not sure how to do this.

Thanks

Answer 1

You can create a page break within a Run element using the <w:br> element. In raw OpenXML, it would look something like:

<w:p>   <w:r>     <w:br w:type="page" />   </w:r> </w:p> 

If you're using the OpenXml SDK, you can use

new Paragraph(   new Run(     new Break(){ Type = BreakValues.Page })); 

EDIT:

If you just want to specify that a paragraph is the last thing on a page, you can try the <w:lastRenderedPageBreak /> tag.

new Paragraph(    new Run(       new LastRenderedPageBreak(),       new Text("Last text on the page"))); 

Answer 2

The PageBreakBefore property accomplishes this. It will insert a page break before your paragraph if Word didn't insert one automatically.

if (myParagraph.ParagraphProperties== null)  {      myParagraph.ParagraphProperties = new ParagraphProperties(); }  myParagraph.ParagraphProperties.PageBreakBefore = new PageBreakBefore(); 

I believe it looks something like this in Open XML:

  <w:p>     <w:pPr>       ...       <w:pageBreakBefore/>          ...     </w:pPr>     ...       </w:p>