Create instance of generic type whose constructor requires a parameter?

Question

Additionally a simpler example:

return (T)Activator.CreateInstance(typeof(T), new object[] { weight });

Note that using the new() constraint on T is only to make the compiler check for a public parameterless constructor at compile time, the actual code used to create the type is the Activator class.

You will need to ensure yourself regarding the specific constructor existing, and this kind of requirement may be a code smell (or rather something you should just try to avoid in the current version on c#).

You can't use any parameterised constructor. You can use a parameterless constructor if you have a "where T : new()" constraint.

It's a pain, but such is life :(

This is one of the things I'd like to address with "static interfaces". You'd then be able to constrain T to include static methods, operators and constructors, and then call them.

Yes; change your where to be:

where T:BaseFruit, new()

However, this only works with parameterless constructors. You'll have to have some other means of setting your property (setting the property itself or something similar).

Most simple solution Activator.CreateInstance<T>()

As Jon pointed out this is life for constraining a non-parameterless constructor. However a different solution is to use a factory pattern. This is easily constrainable

interface IFruitFactory<T> where T : BaseFruit {
  T Create(int weight);
}

public void AddFruit<T>( IFruitFactory<T> factory ) where T: BaseFruit {    
  BaseFruit fruit = factory.Create(weight); /*new Apple(150);*/    
  fruit.Enlist(fruitManager);
}

Yet another option is to use a functional approach. Pass in a factory method.

public void AddFruit<T>(Func<int,T> factoryDel) where T : BaseFruit { 
  BaseFruit fruit = factoryDel(weight); /* new Apple(150); */
  fruit.Enlist(fruitManager);
}