Create an instance of derived class from the base class

Question

I have my abstract base class A:

public abstract class A : ICloneable {

    public int Min { get; protected set; }
    public int Max { get; protected set; }

    public A(int low, int high)
    {
        this.Min = low;
        this.Max = high;
    }

    //...

    public object Clone()
    {
        return new this(this.Min, this.Max); //<-- ??
    }
}

Which is extended by my class B:

public class B : A
{
    public B(int low, int high) : base(low, high) { }

    //...
}

Since A is abstract, it cannot be instantiated, but the derived class can. Is it possible to, from class A, create a new instance of class B?

Suppose class A has many derived classes, how will it know which one to instantiate?

Well, I want to instantiate the same class (or type) my currently A is.

That is, if I'm calling the Clone method from a class B, I want to instantiate a new B. If I'm calling the Clone method from a class C, I want to instantiate a new C.

My approach was to write something like:

return new this(this.Min, this.Max);

But that doesn't seem to work nor compile.

Is it possible to accomplish this in C#?

If it isn't, is there an explanation so I can understand?

Answer 1

Yes, this is possible with an abstract factory method on your base class

public abstract class A
{
   public int Min { get; protected set; }
   public int Max { get; protected set; }

   public A(int low, int high)
   {
       this.Min = low;
       this.Max = high;
   }
   protected abstract A CreateInstance(int low, int high);

   public object Clone()
   {
      return this.CreateInstance(this.Min,this.Max);
   }
}

public class B:A
{
   public B(int low, int high)
      : base(low,high)
   {
   }
   protected override A CreateInstance(int low, int high)
   {
      return new B(low,high);     
   }
}