Create an array with random values

Question

The shortest approach (ES6)

// randomly generated N = 40 length array 0 <= A[N] <= 39
Array.from({length: 40}, () => Math.floor(Math.random() * 40));

Enjoy!

Here's a solution that shuffles a list of unique numbers (no repeats, ever).

for (var a=[],i=0;i<40;++i) a[i]=i;

// http://stackoverflow.com/questions/962802#962890
function shuffle(array) {
  var tmp, current, top = array.length;
  if(top) while(--top) {
    current = Math.floor(Math.random() * (top + 1));
    tmp = array[current];
    array[current] = array[top];
    array[top] = tmp;
  }
  return array;
}

a = shuffle(a);

If you want to allow repeated values (which is not what the OP wanted) then look elsewhere. :)

ES5:

function randomArray(length, max) {
    return Array.apply(null, Array(length)).map(function() {
        return Math.round(Math.random() * max);
    });
}

ES6:

randomArray = (length, max) => [...new Array(length)]
    .map(() => Math.round(Math.random() * max));

Even shorter ES6 approach:

Array(40).fill().map(() => Math.round(Math.random() * 40))

Also, you could have a function with arguments:

const randomArray = (length, max) => 
  Array(length).fill().map(() => Math.round(Math.random() * max))