Create a BufferedImage from file and make it TYPE_INT_ARGB

Question

I have a PNG file with transparency that is loaded and stored in a BufferedImage. I need this BufferedImage to be of TYPE_INT_ARGB. However, when I use getType() the returned value is 0 (TYPE_CUSTOM) instead of 2 (TYPE_INT_ARGB).

This is how I load the .png:

public File img = new File("imagen.png");

public BufferedImage buffImg = 
    new BufferedImage(240, 240, BufferedImage.TYPE_INT_ARGB);

try { 
    buffImg = ImageIO.read(img ); 
} 
catch (IOException e) { }

System.out.Println(buffImg.getType()); //Prints 0 instead of 2

How can I load the .png, save in the BufferedImage and make it TYPE_INT_ARGB?

Answer 1

BufferedImage in = ImageIO.read(img);

BufferedImage newImage = new BufferedImage(
    in.getWidth(), in.getHeight(), BufferedImage.TYPE_INT_ARGB);

Graphics2D g = newImage.createGraphics();
g.drawImage(in, 0, 0, null);
g.dispose();

Answer 2

try {
    File img = new File("somefile.png");
    BufferedImage image = ImageIO.read(img ); 
    System.out.println(image);
} catch (IOException e) { 
    e.printStackTrace(); 
}

Example output for my image file:

BufferedImage@5d391d: type = 5 ColorModel: #pixelBits = 24 
numComponents = 3 color 
space = java.awt.color.ICC_ColorSpace@50a649 
transparency = 1 
has alpha = false 
isAlphaPre = false 
ByteInterleavedRaster: 
width = 800 
height = 600 
#numDataElements 3 
dataOff[0] = 2

You can run System.out.println(object); on just about any object and get some information about it.