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Create a BitmapImage from a byte array

I am creating a byte array with arbitrary values in it and want to convert it into a BitmapImage.

    bi = new BitmapImage();
    using (MemoryStream stream = new MemoryStream(data))
    {
      try
      {
        bi.BeginInit();
        bi.CacheOption = BitmapCacheOption.OnLoad;
        bi.StreamSource = stream;
        bi.DecodePixelWidth = width;

        bi.EndInit();

      }
      catch (Exception ex)
      {
        return null;
      }
    }

This code gives me a NotSupportedException all the time. How could I create a BitmapSource from any byte array?

like image 775
tabina Avatar asked Mar 07 '13 15:03

tabina


2 Answers

Given an array of bytes where each byte represents a pixel value, you may create a grayscale bitmap like shown below. You need to specify the width and height of the bitmap, and that must of course match the buffer size.

byte[] buffer = ... // must be at least 10000 bytes long in this example

var width = 100; // for example
var height = 100; // for example
var dpiX = 96d;
var dpiY = 96d;
var pixelFormat = PixelFormats.Gray8; // grayscale bitmap
var bytesPerPixel = (pixelFormat.BitsPerPixel + 7) / 8; // == 1 in this example
var stride = bytesPerPixel * width; // == width in this example

var bitmap = BitmapSource.Create(width, height, dpiX, dpiY,
                                 pixelFormat, null, buffer, stride);

Each byte value may also represent an index into a color palette, in which case your would have to specify PixelFormats.Indexed8 and of course also pass in an appropriate color palette.

like image 150
Clemens Avatar answered Oct 29 '22 11:10

Clemens


The byte array must contain valid image data (PNG / JPG / BMP). If you remove the using-block and the data is valid then your Code should work. BitmapImage doesn't seem to load the image immediatly, so it can't load it afterwards because the stream is already disposed.

What do you mean by "arbitrary values"? Random RGB values? Then I propose to use the Bitmap class and save the resulting Bitmap in a Memorystream.

If you just want to bind a Byte[] to and Image Control in your userinterface: Bind directly to the array. It works without a converter.

like image 21
doerig Avatar answered Oct 29 '22 10:10

doerig