I am trying to write a query to count the number of records based on a number of different ranges.
I have success with using union
, but I feel there is a better way to do it.
Here is what I've done:
select count(col1) as range1
from tbl1
where col1 <= 15000
union
select count(col1) as range2
from tbl1
where col1 > 15001 and col1 <= 30000
union
select count(col1) as range3
from tbl1
where col1 > 30001 and col1 <= 45000
etc...
I am using sql server 2008. Like I stated above, I'm positive there is a better way to do this, maybe something like this: sql count,
EDIT: Yes, the database is sql 2008, and the answers below work exactly as needed. I forgot to mention that I'm actually reading a JSON
file that has been serialized
via coldfusion serializeJSON
. So in the db, everything below worked perfectly, but coldfusion query of queries doesn't support the CASE
statement, or it doesn't appear to.
The SQL COUNT() function returns the number of rows in a table satisfying the criteria specified in the WHERE clause. It sets the number of rows or non NULL column values. COUNT() returns 0 if there were no matching rows.
To count the number of rows, use the id column which stores unique values (in our example we use COUNT(id) ). Next, use the GROUP BY clause to group records according to columns (the GROUP BY category above). After using GROUP BY to filter records with aggregate functions like COUNT, use the HAVING clause.
Using COUNT, without GROUP BY clause will return a total count of a number of rows present in the table. Adding GROUP BY, we can COUNT total occurrences for each unique value present in the column. we can use the following command to create a database called geeks.
One way is with conditional summation (for the values in separate columns):
select sum(case when col1 <= 15000 then 1 else 0 end) as range1,
sum(case when col1 > 15001 and col1 <= 30000 then 1 else 0 end) as range2,
sum(case when col1 > 30001 and col1 <= 45000 then 1 else 0 end) as range3
from tbl1;
Another way is with group by
(for the values on separate rows):
select (case when col1 <= 15000 then 'range1'
when col1 > 15001 and col1 <= 30000 then 'range2'
when col1 > 30001 and col1 <= 45000 then 'range3'
else 'other'
end) as range, count(*) as cnt
from tbl1
group by (case when col1 <= 15000 then 'range1'
when col1 > 15001 and col1 <= 30000 then 'range2'
when col1 > 30001 and col1 <= 45000 then 'range3'
else 'other'
end);
I often use a subquery for this form:
select range, count(*)
from (select t.*,
(case when col1 <= 15000 then 'range1'
when col1 > 15001 and col1 <= 30000 then 'range2'
when col1 > 30001 and col1 <= 45000 then 'range3'
else 'other'
end) as range
from tbl1
group by range;
That way, the definition of range
only appears once.
EDIT:
The above all use the logic from the OP. However, the above logic misses the values of 15001
and 30001
. My guess is that the OP really means col1 > 15000 and col1 <= 30000
and col1 > 30000 and col1 <= 45000
for the conditions. But, I'm not changing them because the above is how the original question is phrased (perhaps there is something special about 15001
and 30001
).
Personally I prefer using a derived (or physical) table to store my range boundaries which I then join back to in order to find my results.
I reckon the code is simpler and easier to extend if required
Something a little like this:
; WITH ranges (lbound, ubound) AS (
SELECT 0, 1500
UNION ALL SELECT 1500, 3000
UNION ALL SELECT 3000, 4500
)
SELECT ranges.lbound
, ranges.ubound
, Count(your_table.value) As turtle
FROM ranges
LEFT
JOIN your_table
ON your_table.value >= ranges.lbound
AND your_table.value < ranges.ubound
GROUP
BY ranges.lbound
, ranges.ubound
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