"Counter" in Batch

Question

I'm trying to make a Batch file that will increment a variable by 1 each time it loops, and then check if the variable is equal to 5, and if it isn't, it loops again. I know there's probably a while loop for this, but I didn't know how to do that, and I'm just enjoying learning Batch for fun right now

Here's the code, it doesn't work the way it should, it just displays a 0: and then does nothing else. So how would I go about fixing it? I have a feeling I'm setting and incrementing the variable wrong, and maybe it's confused about the 2 if statements? (Does it have an else if....?) Anyways, thanks for the help

@echo off
set /p i=0:
goto A

:A
set /p i=i+1:
if i != 5 goto C
if i == 5 goto B

:C
echo Test :D

:B
pause>nul

Note: I don't know a lot of Batch and I'm not a pro, but I like to learn and I'm just doing this for future reference, and because I enjoy it. So, this code probably isn't good, but I want to know how I can accomplish this.

Answer 1

This is a way to simulate the while loop you are trying to accomplish. Only one goto is needed:

@echo off
set /a x=0
:while
if %x% lss 5 (
  echo %x%
  pause>nul
  set /a x+=1
  goto :while
)
echo Test :D