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echo -e equivalent in Windows?

Is there any Linux "echo -e" equivalent in windows so I can use "echo -e \xnnn" to print out the character whose ASCII code is the hexadecimal value nnn ?

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ccy Avatar asked Dec 21 '10 01:12

ccy


2 Answers

There is no equivalent, but you can write your own function.

I would split the problem into two parts.

  • Convert the hex number to decimal.
  • Convert the decimal number to ASCII.

Converting from hex to decimal is simple by

set "myHex=4A"
set /a decimal=0x%myHex%

Converting a number to an ASCII is more tricky, it depends of the required ASCII-range
If you only need the range from 32 (space) to 126'~', you could use the =ExitCodeAscii variable

set "decimal=%1"
cmd /c exit /b %decimal%
echo "%=ExitCodeAscii%"

If you need also some special characters like CR, LF, ESC, DEL, it is possible to create them with pure batch.

If you need more than you could use vbscript.

forfiles method

A more general way is to use the command forfiles (Dostips: Generate nearly any character...)

echo-e.bat

@echo off
set "arg1=%~1"
set "arg1=%arg1:\x=0x%"
forfiles /p "%~dp0." /m "%~nx0" /c "cmd /c echo(%arg1%"

You can call it via echo-e.bat "Hello\x01\x02\x03" and you get Hello☺☻♥.

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jeb Avatar answered Nov 08 '22 13:11

jeb


There is a batch file character manipulation library written by Dave Benham called CharLib. This library, amongst other things, is able to convert hex to ascii, for all characters in the range 1..255 (it can't to 0 -> NUL).

For more info see the thread Is it possible to convert a character to its ASCII value? on DosTips.com

If you just need to use a single problematic character (e.g. a control code) in your batch script, then it's an invaluable resource for a cut and paste.

e.g. to print a CR character (without LF) in a batch script...

@echo off
setlocal enableextensions enabledelayedexpansion
for /f %%a in ('copy /Z "%~dpf0" nul') do set "ASCII_13=%%a"
echo 1234567890!ASCII_13!xxxxxx

will end up printing "xxxxxx7890" on the console as expected.

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timfoden Avatar answered Nov 08 '22 12:11

timfoden