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Couldn't find Listing with 'id'=all, Search Form

So this is very weird. I followed this railscast http://railscasts.com/episodes/37-simple-search-form and after I implemented everything it looked like this

index.html.erb

<%= form_tag findjobs_path, :method => 'get' do %>
      <p>
      <%= text_field_tag :search %>
      <%= submit_tag "search" %>
       </p>
<% end %>

listings_controller.rb

    def index
    @listings = Listing.all
    @listings = Listing.paginate(:page => params[:page], :per_page => 10)
    @user = User.find_by_name(params[:name])
    @listing = Listing.find_by_id(params[:id])
    @categories = Category.all
    @listings = Listing.search(params[:search])
    end
end

listing.rb

def self.search(search)
  if search
    find(:all, :conditions => ['name LIKE ?', "%#{search}%"])
  else
    find(:all)
  end
end

I get the following error: Couldn't find Listing with 'id'=all I understand that the find methods looks right away for the id. I however don't know how I need to set it so that it searches through all my listings. find_by_all of course does not work.

I hope anyone can help

Thank you so muc

like image 824
Rika Avatar asked Sep 11 '14 00:09

Rika


1 Answers

how about modify listing.rb search method?

def self.search(search)
  if search
    self.where("name like ?", "%#{search}%")
  else
    self.all
  end
end

Plus..

listings_controller.rb

def index
  @listings = Listing.all 
  # Patching all Listing

  @listing = Listing.where(id: params[:id]) if params[:id].present?
  # Find By Id (For pagination, the 'where' statement result is Listing ActiveRecord::Relationship )
  @listings = @listings.search(params[:search]) if params[:search].present?
  # Search using Keyword
  @listings = @listings.paginate(:page => params[:page], :per_page => 10)
  # Pagination
  @user = User.find_by_name(params[:name]) if params[:name].present?
  # Find User using name column
  @categories = Category.all

end
like image 71
kai Avatar answered Sep 17 '22 03:09

kai