Could not find an overload for '/' that accepts the supplied arguments

Question

// Playground - noun: a place where people can play   func getAverage(numbers: Int...) -> Double{     var total = 0     var average:Double = 0      for number in numbers{         total = total + number     }      average = total / numbers.count      return average }  getAverage(3, 6) 

I get an error on average = total / numbers.count

Could not find an overload for '/' that accepts the supplied arguments

I tried to fix by doing:

average = Double(total/numbers.count) 

but then the getAverage was set to 4 instead of 4.5

Answer 1

There are no such implicit conversions in Swift, so you'll have to explicitly convert that yourself:

average = Double(total) / Double(numbers.count) 

From The Swift Programming Language: “Values are never implicitly converted to another type.” (Section: A Swift Tour)

But you're now using Swift, not Objective-C, so try to think in a more functional oriented way. Your function can be written like this:

func getAverage(numbers: Int...) -> Double {     let total = numbers.reduce(0, combine: {$0 + $1})     return Double(total) / Double(numbers.count) } 

reduce takes a first parameter as an initial value for an accumulator variable, then applies the combine function to the accumulator variable and each element in the array. Here, we pass an anonymous function that uses $0 and $1 to denote the first and second parameters it gets passed and adds them up.

Even more concisely, you can write this: numbers.reduce(0, +).

Note how type inference does a nice job of still finding out that total is an Int.