Swift: how to return class type from function

Question

I know it is possible to pass class type to a function in swift:

func setGeneric<T>(type: T.Type){ } setGeneric(Int.self) 

But how we can return type from function? Writing something like

func getGeneric<T>() -> T.Type {    return Int.self } 

gives compiler error "Int is not identical to T". So is it possible to return type from a swift function?

Edit
Some explanation. I have classes that are used for persistence (I'm using Realm) and I have classes that acts as wrappers around this classes. All wrappers inherits from RealmClassWrapper which needs to know what Realm class it actually wraps. So lets say I have this realm model:

class RealmTodo: RLMObject {    dynamic var title = "" } 

and my wrappers supper class looks like this:

class RealmClassWrapper {    private let backingModel: RLMObject    //...    func backingModelType<T>() -> T.Type{ fatalError("must be implemented") } } 

and actual wrapper:

class Todo: RealmClassWrapper {    //some other properties    func backingModelType<T>() -> T.Type{ return RealmTodo.self } } 

Answer 1

You can return any type you want.

func getTypeOfInt()  -> Int.Type  { return Int.self  } func getTypeOfBool() -> Bool.Type { return Bool.self } 

If the type is not determined from arguments or if the return is constant, there is no need to introduce a generic T type.

Answer 2

It works when I modify your function like this:

func getGeneric<T>(object: T) -> T.Type {     return T.self }  getGeneric(0)    // Swift.Int