Correct way to cast a JSON object into a typescript typed variable using a class?

Question

This is a more simple example of what I'm trying to do:

export class Person{
    id:Number;
    name:String;
}

export class PersonForm{

    // This line:
    default:Person = {name: "Guy"};
    // Gives the following error:
    //  Error:(25, 5) TS2322: Type '{ name: string; }' is not assignable to type 'Person'.
    //  Property 'id' is missing in type '{ name: string; }'.

    // I tried <Person>{name: "Guy"} but it gives the same error.

}

How can I make the compiler ignore this issue as long as Im not using non existant properties, or how do I declare the class so I can do the assignment this way instead of new Person() and then setting just the properties I want.

Note: Sending an object with all the properties into the constructor is not the solution I'm expecting. Also using an interface works because I can declare the fields optional, how can I do the same in a class?

Adding some more info:

The main goal of what I'm trying to achieve:

Find the best way to declare a class (not an interface) so I can initialize it with clean code in one line setting only the parameters I want to set. In Java you would overload constructors or use the Builder pattern.

I could certainly try the builder pattern but I'm looking for a more typescript way to do it, if there's any.

Answer 1

I found the easiest way to do it, and IT IS POSSIBLE. I think I had tried it this way before but the fact that I was using the "Number" & "String" types instead of "number" & "string", might be giving me missleading errors from the compiler, the following code works wonders for me:

export class Person{
    constructor(
        public id?: number, // make sure you use number and string types instead of Number and String types
        public name?: string // make sure you make all properties optional using "?"
    ){}
}

export class PersonForm{
    default:Person = <Person>{name: "Guy"};
}