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When I build a Visual Studio project, the executable is written to the output directory specified in the projects Property Page.
I have a project that has some extra files (e.g., .ini file) that are used by the program.
How can I configure the project to copy the file to the output directory so that when the program runs, it has a copy of the other file in its CWD?
I checked the Property Page of the file and there was nothing useful other than an option to exclude it from the build (which is disabled), and the custom-build-tool command is empty (plus it is a plain-text file that does not need any processing).
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"Copy to Output Directory" is the property of the files within a Visual Studio project, which defines if the file will be copied to the project's built path as it is. Coping the file as it is allows us to use relative path to files within the project.
To place all solution outputs in a common directory Click on one project in the solution. On the Project menu, click Properties. In each project, depending on its type, select either Compile or Build, and set the Output path or Base output path to a folder to use for all projects in the solution.
For copying a files to the output directory in Visual Studio 2003 you could use Post-Build event:
Set Post-Build Event Command Line to:
xcopy /y $(ProjectDir)my_file.ini $(ProjectDir)$(OutDir) OK and build!
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