Copy contents of all files into one file in bash different sequence

Question

I need to combine all files in a folder to a single file.
Files are named as t1, t2, t3, ..., t1500 and output file is "all".
I've used the following command in bash: cat t* >> all
but it combines files in the sequence t1, t10, t11, ... instead of t1, t2, t3, ...
Any help please.

Answer 1

You can try

cat t{1..1500} > all

If you get any error involving a too-long command line, you can try

for i in {1..1500}; do
  echo "t$i"
done | xargs -n 1500 cat

A longer, but arguably more readable, method that manually splits the list up between multiple calls to cat:

{ cat t{1..100}
  cat t{101..500}    
  cat t{601..1000}
  cat t{1001..1500}
} > all

Answer 2

Mine:

find -maxdepth 1 -regextype posix-egrep -regex '.*t[[:digit:]]+$' | sort -V | xargs cat > all

Or

shopt -s extglob
printf "%s\n" t+([[:digit:]]) | sort -V | xargs cat > all

Or perhaps simply (if applicable):

printf "%s\n" t* | sort -V | xargs cat > all