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How can I convert a string of digits to an integer ? I want "365" to be converted to 365.
What I have tried, string->list then char->integer, but this returns ASCII value of that integer, how can I get that integer ?
Please help.
264
The unary plus operator ( + ) will convert a string into a number. The operator will go before the operand. We can also use the unary plus operator ( + ) to convert a string into a floating point number. If the string value cannot be converted into a number then the result will be NaN .
One effective way to convert a string object into a numeral int is to use the stoi() function. This method is commonly used for newer versions of C++, with is being introduced with C++11. It takes as input a string value and returns as output the integer version of it.
To convert, or cast, a string to an integer in Python, you use the int() built-in function. The function takes in as a parameter the initial string you want to convert, and returns the integer equivalent of the value you passed.
Try: string->number
> (string->number "1234")
1234
An alternative solution to parse integers from strings:
#lang typed/racket
(: numerical-char->integer (-> Char
Integer))
(define (numerical-char->integer char)
(let ([num (- (char->integer char) 48)]) ; 48 = (char->integer #\0)
(if
(or (< num 0) (> num 9))
(raise 'non-numerical-char #t)
num)))
(: string->integer (-> String
Integer))
(define (string->integer str)
(let ([char-list (string->list str)])
(if (null? char-list)
(raise 'empty-string #t)
(foldl
(λ([x : Integer] [y : Integer])
(+ (* y 10) x))
0
(map numerical-char->integer char-list)))))
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