Imagine I make an request to my api that return an mysql_query("Select * from user where id=1")
.
After the request is done, it returns the user info in json.
I do some debuging, NSlog(@"JSON : %@",json);
and it gives me this:
JSON : (
{
aboutme = "";
active = 0;
birthday = "1992-10-14";
"city_id" = 0;
email = "[email protected]";
fbid = "";
firstname = test;
gender = 1;
id = 162;
lastname = test;
password = "$2a$12$8iy.sGr.4V/Ea3GfHZe0m.SLDrvoSj3/wYRlWsNce1yyCMeCbDrMC";
"phone_number" = "";
"recovery_date" = "0000-00-00 00:00:00";
"register_date" = "2013-06-06 02:44:20";
salt = "8iy.sGr.4V/Ea3GfHZe0m";
"user_type_id" = 1;
username = test;
}
)
Now I parse it with AFJONDecode
and when I get the [json valueForKey:@"username"];
and debug it ( NSlog(@"username = %@",[json valueForKey@"username"]);
) and I get this:
username = (
testeteste739
)
It gives me an object ( because in the Json, the username = test and not username = "test").
So, how can i convert this object to string?
** UPDATE **
I resolve it by the following way:
NSArray *username = [JSON valueForKey:@"username"];
username = [username objectAtIndex:0];
Is there any better way to overpass this? Thanks
Use the JavaScript function JSON.stringify() to convert it into a string. const myJSON = JSON.stringify(obj); The result will be a string following the JSON notation.
The JSON.stringify() method converts a JavaScript value to a JSON string, optionally replacing values if a replacer function is specified or optionally including only the specified properties if a replacer array is specified.
Example - Parsing JSONUse the JavaScript function JSON.parse() to convert text into a JavaScript object: const obj = JSON.parse('{"name":"John", "age":30, "city":"New York"}'); Make sure the text is in JSON format, or else you will get a syntax error.
As JSON is a dictionary object, so you can get your json data to JSONDic NSDictionary variable and parse it to string as follows:-
NSDictionary *JSONDic=[[NSDictionary alloc] init];
NSError *error;
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:JSONDic
options:NSJSONWritingPrettyPrinted
error:&error];
NSString *jsonString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With