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Converting an array of bytes to an array of floats

I'm currently converting a Delphi method used for random binary file access into Java. The Delphi procedure uses:

TSingleArray  = Array[0..MAXSIZE] of Single
...
procedure GetLinkValues(const LinkVar: Integer;  const TimePeriod: Integer; var Value: PSingleArray);
...
BlockRead(Fout, Value^, Nlinks*SizeOf(Single));

To read an array of bytes into an array of Single. Is there an equivalent way of doing this in Java without iterating through the array?

I’m currently using

List<Float> l = new ArrayList<Float>();
…
for (int i = 0 ; i < nLinks ; i++ )
l.add( resultsFile.readFloat());

But I’m concerned about speed. Endianness is not a problem.

like image 739
GrahamA Avatar asked Feb 20 '09 16:02

GrahamA


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1 Answers

Have you profiled the code and actually found it to be a problem? Something is going to have to loop... are you really sure this is a bottleneck in your code?

Having said all that, you should be able to use a FloatBuffer which I suspect does what you want. Unfortunately Sun's JavaDoc is down, so I can't easily link to or check the documentation at the minute.

To use a FloatBuffer, you'd probably want to:

  • Create a FileChannel associated with the file (e.g. with FileInputStream.getChannel)
  • Create a ByteBuffer
  • Create a FloatBuffer wrapping the ByteBuffer, with ByteBuffer.asFloatBuffer
  • Read into the ByteBuffer with FileChannel.read(byteBuffer)
  • Read from the FloatBuffer

I'm not particularly familiar/comfortable with java.nio, so I hope this is all correct - but it's likely to be pretty fiddly. Your current loop is almost certainly simpler, so I strongly suggest you check the performance of that first! You might want to wrap your current FileInputStream in a BufferedInputStream, btw.

like image 118
Jon Skeet Avatar answered Oct 13 '22 23:10

Jon Skeet