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Converting a StringIO object to a Django ImageFile

I'm trying to take data from a StringIO (or cStringIO, more specifically) and convert it to a django.core.files.images.ImageFile.

But it doesn't work. Any by that, I mean that it fails in a multitude of ways, and Google has failed me.

So far I've got:

pi = ProductImage(product=product)
image = ImageFile(image_file)
image.name = image_name # defined elsewhere
pi.source_image.save(image_name, image)
pi.save()

My stack trace goes something like this:

File "dev.py", line 359, in process_csv_item
  pi.source_image.save(image_name, image)
File "C:\Python26\lib\site-packages\django\db\models\fields\files.py", line 92, in save
  self.name = self.storage.save(name, content)
File "C:\Python26\lib\site-packages\django\core\files\storage.py", line 48, in save
  name = self._save(name, content)
File "C:\Python26\lib\site-packages\django\core\files\storage.py", line 168, in _save
  for chunk in content.chunks():
File "C:\Python26\lib\site-packages\django\core\files\base.py", line 65, in chunks
  counter = self.size
File "C:\Python26\lib\site-packages\django\core\files\base.py", line 39, in _get_size
  elif os.path.exists(self.file.name):
AttributeError: 'cStringIO.StringI' object has no attribute 'name'

Where can I look next?

like image 395
Brian Hicks Avatar asked Apr 06 '11 20:04

Brian Hicks


1 Answers

Use django.core.files.base.ContentFile(image_file):

pi = ProductImage(product=product)
pi.source_image.save(image_name, ContentFile(image_file.read()))
pi.save()
like image 78
gcbirzan Avatar answered Nov 06 '22 19:11

gcbirzan