Converting a hexadecimal Integer into a character using explicit type conversion?

Question

I coded the following, But the o/p is not the expected ? Someone Guide me?

Question: Write a sample program to declare a hexadecimal integer and covert it into a character using explicit type Conversion?

class hexa
{
public static void main(String ar[])
{
    int hex=0xA;
    System.out.println(((char)hex));
}
}

please tell me : Why there is a difference in output

/*code 1*/
int hex = (char)0xA; 
System.out.println(hex); 
/*code 2*/
int hex = 0xA; 
System.out.println((char)hex);

Answer 1

int hex = 0xA; 
System.out.println( (char)hex );

The hex value 0xA (or decimal 10) is "\n" (new line feed char) in ASCII.
Hence the output.

EDIT (thanks to halex for providing the correction in comments:

int hex = (char) 0xA;
System.out.println(hex); //here value of hex is '10', type of hex is 'int', the overloaded println(int x) is invoked.

int hex = 0xA;
System.out.println((char) hex); //this is equivalent to System.out.println( '\n' ); since the int is cast to a char, which produces '\n', the overloaded println(char x) is invoked.

Answer 2

I assume you want the letter A to be printed. Instead of print use printf.

int hex=0xA;
System.out.printf("%X%n", hex);