Converting a float to hh:mm format

Question

I want to print a float value that I've got after performing some math as time string in the hh:mm format. Currently I have the float like 9.888888888888886 and I want it in time like 09:50. I have tried the following code:

    time = str(time)
    time = time.split(".")
    time[1] = float(time[1])
    time[1] *= 0.6
    time[1] = str(time[1])

and when I print I use

    str(time[0]) + ":" + time[1][:2]

Any way to achieve this effect consistently? With more advanced inputs my above code does not work properly, and outputs the wrong time.

Answer 1

For python 3.7 version this becomes an one-liner.

x = 9.888888888888886

print (str(datetime.timedelta(hours=x))[:-3])

(Here the time-string minus the last three chars is printed.)

Result 1 : 9:53

Alternatively if you needs seconds:

print (datetime.timedelta(hours=x))

Result 2 : 9:53:20

And finally if you go beyond the 24hour mark timedelta shows the added day as well:

x = 39.888888888888886

Result 3 : 1 day, 15:53:20