How to convert "2011-11-03T17:27:56Z"
to time in php.
I want time difference from current time.
i.e. if time difference from current time is 10 minutes the I want 10 minutes. If its 1 day then I want 1 day.
We can convert a string to datetime using strptime() function. This function is available in datetime and time modules to parse a string to datetime and time objects respectively.
The strtotime() function parses an English textual datetime into a Unix timestamp (the number of seconds since January 1 1970 00:00:00 GMT). Note: If the year is specified in a two-digit format, values between 0-69 are mapped to 2000-2069 and values between 70-100 are mapped to 1970-2000.
echo "The time is " . date("h:i:sa"); ?> Note that the PHP date() function will return the current date/time of the server!
Description ¶ time(): int. Returns the current time measured in the number of seconds since the Unix Epoch (January 1 1970 00:00:00 GMT). Note: Unix timestamps do not contain any information with regards to any local timezone.
This little snippet will give you the difference in seconds between now and the given date.
$dateString = "2011-11-03T17:27:56Z";
$date = strtotime($dateString);
$diff = time() - $date;
echo $diff;
To give it the specific format you're asking for you can use the below function I found here:
function time_diff($s) {
$m = 0; $hr = 0; $d = 0; $td = "now";
if ($s > 59) {
$m = (int)($s/60);
$s = $s-($m*60); // sec left over
$td = "$m min";
}
if ($m > 59) {
$hr = (int)($m / 60);
$m = $m - ($hr*60); // min left over
$td = "$hr hr";
if ($hr > 1) {
$td .= "s";
}
if ($m > 0) {
$td .= ", $m min";
}
}
if ($hr > 23) {
$d = (int) ($hr / 24);
$hr = $hr-($d*24); // hr left over
$td = "$d day";
if ($d > 1) {
$td .= "s";
}
if ($d < 3) {
if ($hr > 0) {
$td .= ", $hr hr";
}
if ($hr > 1) {
$td .= "s";
}
}
}
return $td;
}
Combining the both this is what you get:
$dateString = "2011-11-03T17:27:56Z";
$date = strtotime($dateString);
$diff = time() - $date;
echo time_diff($diff);
Outputs:
8 days
$diffInSecs = time() - strtotime('2011-11-03T17:27:56Z');
Working example: (codepad here)
<?php
$time_str = "2011-11-03T17:27:56Z";
//echo date('d/m/y H:i:s', strtotime($time_str));
$diff = abs(strtotime("now") - strtotime($time_str));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
$hours = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24)/ (60*60));
$minuts = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60)/ 60);
$seconds = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60 - $minuts*60));
printf("%d years, %d months, %d days, %d hours, %d minuts\n, %d seconds\n", $years, $months, $days, $hours, $minuts, $seconds);
(time diff took here: How to calculate the difference between two dates using PHP?)
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