Input:
www.example.com/1/2/index.php../../index.phpOutput:
www.example.com/index.phpIt would be perfect, of it would be done using sed.
As I understand, this regex should delete one somefolder/ in for every ../ in the URL.
realpath is a quick but slightly hacky way to do what you want.
(Actually, I'm surprised that it doesn't deal properly with URLs; it treats them as plain old filesystem paths.)
~$ realpath -m http://www.example.com/1/2/../../index.php =>
~$ /home/username/http:/www.example.com/index.php
The -m (for "missing") says to resolve the path even if components of it don't actually exist on the filesystem.
So you'll still have to strip off the actual filesystem part of that (which will just be $(pwd). And note that the slash-slash for the protocol was also canonicalized to a single slash. So you might be better off to leave the "http://" off of your input and just prepend it to your output instead.
See man 1 realpath for the full story. Or info coreutils 'realpath invocation' for a more verbose full story, if you have the info system installed.
Using sed inside bash
#!/bin/bash
base_url='www.example.com/1/2/index.php'
rel_url='../../index.php'
str="${base_url};${rel_url}"
str=$(echo $str | sed -r 's#/[^/]*;#/#')
while [ ! -z $(echo $str | grep '\.\.') ]
do
str=$(echo $str | sed -r 's#\w+/\.\./##')
done
abs_url=$str
echo $abs_url
Output:
www.example.com/index.php
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