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Solution 3. CString MyString; int MyInt; MyString. Format(L"%d",MyInt); Another way is to use the std library's to_wstring[^], and then cast the result to CString.
CString pi = "3.14"; return _ttof(pi); Reading a string value and parse/convert it to float allows you to locate the error when there is one. All you need is a help of a C Run-time function: strtod() or atof().
One effective way to convert a string object into a numeral int is to use the stoi() function. This method is commonly used for newer versions of C++, with is being introduced with C++11. It takes as input a string value and returns as output the integer version of it.
To use a CString object as a C-style string, cast the object to LPCTSTR . In the following example, the CString returns a pointer to a read-only C-style null-terminated string. The strcpy function puts a copy of the C-style string in the variable myString .
If you are using TCHAR.H routine (implicitly, or explicitly), be sure you use _ttoi() function, so that it compiles for both Unicode and ANSI compilations.
More details: https://msdn.microsoft.com/en-us/library/yd5xkb5c.aspx
The simplest approach is to use the atoi() function found in stdlib.h:
CString s = "123";
int x = atoi( s );
However, this does not deal well with the case where the string does not contain a valid integer, in which case you should investigate the strtol() function:
CString s = "12zzz"; // bad integer
char * p;
int x = strtol ( s, & p, 10 );
if ( * p != 0 ) {
// s does not contain an integer
}
CString s;
int i;
i = _wtoi(s); // if you use wide charater formats
i = _atoi(s); // otherwise
A _ttoi function can convert CString to integer, both wide char and ansi char can work. Below is the details:
CString str = _T("123");
int i = _ttoi(str);
you can also use good old sscanf.
CString s;
int i;
int j = _stscanf(s, _T("%d"), &i);
if (j != 1)
{
// tranfer didn't work
}
CString s="143";
int x=atoi(s);
or
CString s=_T("143");
int x=_toti(s);
atoi will work, if you want to convert CString to int.
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