How do I convert a hex string to an int in Python?
I may have it as "0xffff
" or just "ffff
".
You can convert the hexstring to an integer in Python using the literal_eval() method of the ast (Abstract Syntax Trees) library. We have to pass the hex string to the literal_eval() function, there are no parameters, the function converts the hex string into an integer.
To convert a hexadecimal string to a numberUse the ToInt32(String, Int32) method to convert the number expressed in base-16 to an integer. The first argument of the ToInt32(String, Int32) method is the string to convert. The second argument describes what base the number is expressed in; hexadecimal is base 16.
To convert, or cast, a string to an integer in Python, you use the int() built-in function. The function takes in as a parameter the initial string you want to convert, and returns the integer equivalent of the value you passed. The general syntax looks something like this: int("str") .
hex() function in Python hex() function is one of the built-in functions in Python3, which is used to convert an integer number into it's corresponding hexadecimal form. Syntax : hex(x) Parameters : x - an integer number (int object) Returns : Returns hexadecimal string.
Without the 0x prefix, you need to specify the base explicitly, otherwise there's no way to tell:
x = int("deadbeef", 16)
With the 0x prefix, Python can distinguish hex and decimal automatically.
>>> print(int("0xdeadbeef", 0)) 3735928559 >>> print(int("10", 0)) 10
(You must specify 0
as the base in order to invoke this prefix-guessing behavior; if you omit the second parameter int()
will assume base-10.)
int(hexstring, 16)
does the trick, and works with and without the 0x prefix:
>>> int("a", 16) 10 >>> int("0xa", 16) 10
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