Convert datetime field to just a date field in SQL (Oracle)

Question

I've seen a few answers to questions similar to mine but I cannot get them to work. I have several date fields in my query that return the date and time like such 7/1/2014 12:00:00 AM. Is there a way I can just have the fields show 7/1/2014?

SELECT DISTINCT
C.RECEIPTDATE,
(I.CLIENTID ||' - '||PO.CLIENTNAME) AS CLIENT,
D.INVOICEID,
D.SVCFROMDATE,
D.SVCTODATE,
D.SVCCODE
FROM M_EQP_ORDERS
WHERE.....

I basically would like to cut down the two date fields to the shorter date format minus the time.

Thanks in advance!

Answer 1

Just use the function TRUNC.

SELECT DISTINCT
TRUNC(C.RECEIPTDATE),
(I.CLIENTID ||' - '||PO.CLIENTNAME) AS CLIENT,
D.INVOICEID,
TRUNC(D.SVCFROMDATE),
TRUNC(D.SVCTODATE),
D.SVCCODE
FROM M_EQP_ORDERS
WHERE.....

Answer 2

Use to_char function:

SELECT DISTINCT
to_char(C.RECEIPTDATE,'DD/MM/YYYY'),
(I.CLIENTID ||' - '||PO.CLIENTNAME) AS CLIENT,
D.INVOICEID,
D.SVCFROMDATE,
D.SVCTODATE,
D.SVCCODE
FROM M_EQP_ORDERS
WHERE.....